2x^2-16x+39=0

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Solution for 2x^2-16x+39=0 equation:


Simplifying
2x2 + -16x + 39 = 0

Reorder the terms:
39 + -16x + 2x2 = 0

Solving
39 + -16x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
19.5 + -8x + x2 = 0

Move the constant term to the right:

Add '-19.5' to each side of the equation.
19.5 + -8x + -19.5 + x2 = 0 + -19.5

Reorder the terms:
19.5 + -19.5 + -8x + x2 = 0 + -19.5

Combine like terms: 19.5 + -19.5 = 0.0
0.0 + -8x + x2 = 0 + -19.5
-8x + x2 = 0 + -19.5

Combine like terms: 0 + -19.5 = -19.5
-8x + x2 = -19.5

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -19.5 + 16

Reorder the terms:
16 + -8x + x2 = -19.5 + 16

Combine like terms: -19.5 + 16 = -3.5
16 + -8x + x2 = -3.5

Factor a perfect square on the left side:
(x + -4)(x + -4) = -3.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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